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-0.0152x^2+2.6356x-9.9001=50
We move all terms to the left:
-0.0152x^2+2.6356x-9.9001-(50)=0
We add all the numbers together, and all the variables
-0.0152x^2+2.6356x-59.9001=0
a = -0.0152; b = 2.6356; c = -59.9001;
Δ = b2-4ac
Δ = 2.63562-4·(-0.0152)·(-59.9001)
Δ = 3.30446128
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(2.6356)-\sqrt{3.30446128}}{2*-0.0152}=\frac{-2.6356-\sqrt{3.30446128}}{-0.0304} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(2.6356)+\sqrt{3.30446128}}{2*-0.0152}=\frac{-2.6356+\sqrt{3.30446128}}{-0.0304} $
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